Question 1051112
 {{{y=2x-3}}}...here you have a linear function  and the graph will be a line

since  line is uniquely determined by two points,  to graph it you find two points that lie on a line

{{{y=2x-3}}}.....if {{{x=0}}}
{{{y=2*0-3}}}
{{{y=-3}}}

so, one point is y-intercept at ({{{0}}},{{{-3}}})

{{{y=2x-3}}}.....if {{{y=0}}}
{{{0=2x-3}}}
{{{2x=3}}}
{{{x=3/2}}}
so, the other point is x-intercept at ({{{3/2}}},{{{0}}})

plot these points and draw a line through

{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(0,-3,.12),circle(3/2,0,.12),
locate(3/2,0.95,p(3/2,0)),locate(0,-3,p(0,-3)),
 graph( 600, 600, -10, 10, -10, 10, 2x-3)) }}}