Question 1051081
(x^2*e^x)/(x^2+e^x)
The derivative will have the above denominator squared as the denominator.  
The result will be (x^2+e^x)(2x*e^x+x^2*e^x)-(x^2*e^x)(2x+e^x)/[x^2+e^x)^2]
If you multiply the numerator out, it is 2x^3*e^x+x^4*e^x+2x*e^2x+x^2*e^2x-
2x^3*e^x-x^2*e^2x.
The 2x^3*e^x and x^2*e^2x cancel
The answer can be written as (x^4*e^x+2x*e^2x)/(x^2+e^x)^2.