Question 1051012
<pre><b>

First we draw the graph of  y = 3|x - 2| the boundary
graph by getting 

1. the vertex when what's between the absolute
value bars equals 0:

   x - 2 = 0
       x = 2

Substitute in y = 3|x - 2|
              y = 3|2 - 2|
              y = 3|0|
              y = 3&#8729;0
              y = 0

So the vertex is (2,0)

2. Get a point on the left side of 2, (1,3) 
3. Get a point on the right side of 2, (3,3)

Draw the graph dotted because its <, not <u><</u>

{{{drawing(400,400,-10,10,-10,10,

graph(400,400,-10,10,-10,10,(3*abs(x-2))*sqrt(sin(15x))/sqrt(sin(15x))) )}}}

Now shade BELOW the graph because it's " y < ":
{{{drawing(400,400,-10,10,-10,10,
graph(400,400,-10,10,-10,10,20,


y<3*abs(x-2)-.4),

graph(400,400,-10,10,-10,10,(3*abs(x-2))*sqrt(sin(15x))/sqrt(sin(15x))) )}}}

Edwin</pre></b>