<PRE><B>Question 1050894</B>
(x+4)^2+x(x+2)=268
x^2+8x+16+x^2+2x=268
2x^2+10x+16=268
x^2+5x+8=134
x^2+5x-126=0
(x-9)(x+14)=0  Note: Just the sign here
x=9, x=-14 (discard)
three consecutive odd integers = 9,11,13 
checking
169 + 99 = 268 CHECKS!
Good work.</PRE>