Question 1050856
22 students, 12 female and 10 males
3 selected w/o replacement
RE: TY, what are the "right answers" You are attempting to get?
a) What is the probability that a male is selected, then two females? 
P = {{{(10/22)(12/21)(11/20) = ((10*12*11)/(22*21*20))}}} = 6/42 = 1/7
Recommend Multiplying numerators and denominators - and then canceling out where You can.
(b) What is the probability that a female is selected, then two males? 
P = {{{(12/22)(10/21)(9/20)}}} = 9/77
(c) What is the probability that two females are selected, then one male? 
P = {{{(12/22)(11/21)(10/20)}}} = 1/7
(d) What is the probability that three males are selected? 
P = {{{(10/22)(9/21)(8/20)}}} = 6/77
(e) What is the probability that three females are selected? 
P = {{{(12/22)(11/21)(10/20)}}} = 1/7