Question 1050840
The area of a rectangle is √125 cm squared
The length is (2+√5)
Calculate the width of the rectangle giving your answer in the form a+b√5 where a and b are integers
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W = {{{sqrt(125)/(2 + sqrt(5))}}}
Multiply NUM and DEN by the conjugate of the DEN
W = {{{sqrt(125)*(2 - sqrt(5))/((2 + sqrt(5))*(2 - sqrt(5)))}}}
W = {{{sqrt(125)*(2 - sqrt(5))/(-1))}}}
W = {{{-sqrt(125)*(2 - sqrt(5))}}}
W = {{{-2sqrt(125) + sqrt(625))}}}
W = {{{25 - 10sqrt(5)}}}