Question 1050756
The other complex zero of {{{3+2i}}} is needed.


{{{f(x)=(x-(-3))(x-(3-2i))(x-(3+2i))}}}


{{{(x+3)(x-3+2i)(x-3-2i)}}}


{{{(x+3)((x-3)+2i)((x-3)-2i)}}}


{{{(x+3)((x-3)^2-(-1)4)}}}


{{{(x+3)(x^2-6x+9+4)}}}


{{{(x+3)(x^2-6x+13)}}}


{{{x^3-6x^2+13x+3x^2-18x+39}}}


{{{highlight(x^3-3x^2-5x+39)}}}