Question 1050756
[x -(3-2i)][x -(3+2i)] = [x -3 + 2i][x-3 -2i] = (x-3)^2 -(2i)^2 = x^2-6x + 9 + 4
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(x+3)(x^2 - 6x + 13) = x^3 - 6x^2 + 13x + 3x^2 - 18x + 39 = x^3-3x^2 - 5x + 39
Check Arithmetic