<PRE><B>Question 1050730</B>
Jack cycled from A to B at an average speed of 20km/h. He then cycled back from B to A at an average speed of 18km/h. If he took a total of 1 hour 35 minutes, find the distance between A and B?



Cycle
speed 20
time t
distance 20t


cycle back
speed 18
time 19/12-t
distance 18(19/12-t)

20t=18(19/12-t)
20t=(3*19)/2-18t
t=(3*19)/2

t={{{57/76}}}

now calculate the distance
20(57/76)=distance
15km=Distance</PRE>