Question 1050724
the probability of having the particular blood type is:
type o = .53
type a = .21
type b = .03
type ab = .23


the probability of having type o is .53.


the probability of not having type o is 1 - .53 = .47


the sum of all probabilities has to be equal to 1.


.53 + .21 + .03 + .23 = 1.


the probabilities are correct.


the probability of not having type o is also the probability of having any of the other 3 types.


that would be equal to .21 + .03 + .23 = .47.


the general formula would be p(not a) is equal to 1 - p(a), where a is the event.


in this case, the event is having blood type O.