Question 1050553
Convert the equation to vertex form,
{{{h=-5t^2+10t+0.8}}}
{{{h=-5(t^2-2t)+0.8}}}
{{{h=-5(t^2-2t+1)+0.8+5}}}
{{{h=-5(t-1)^2+5.8}}}
a) Since it's in vertex form, {{{h[max]=5.8}}}{{{m}}}
b) Since it's in vertex form, {{{t[max]=1}}}{{{s}}}
c) Set {{{h=0}}},
{{{-5(t-1)^2+5.8=0}}}
{{{5(t-1)^2=5.8}}}
{{{(t-1)^2=(5.8/5)}}}
{{{t-1=sqrt(5.8/5)}}}
{{{t=1+sqrt(5.8/5)}}}{{{s}}}