Question 91654
(x-1)^2=7 
{{{(sqrt(x-1)^2)}}}={{{(sqrt(7))}}} [take the square root of both sides]
x-1={{{(sqrt(7))}}}
x={{{(1+-sqrt(7))}}}
.
.

and also X^2-9x-4=6 
{{{(x^2-9x-4-6)}}}=0 
{{{(x^2-9x-10)}}}=0
(x-10)(x+1)
.
Set each factor equal to zero and solve for the x-value:
x-10=0
x=10
and
x+1=0
x=-1