Question 91744
Solve for x using the quadratic formula: {{{x = (-b+-sqrt(b^2-4ac))/2a}}}
Problem 1.
{{{2x^2-5x = 3}}} Subtract 3 from both sides to get your equation into standard form: {{{ax^2+bx+c = 0}}}
{{{2x^2-5x-3 = 0}}} Apply the formula:
{{{x = (-(-5)+-sqrt((-5)^2-4(2)(-3)))/2(2)}}} Now evaluate this.
{{{x = (5+-sqrt(25+24))/4}}}
{{{x = (5+-sqrt(49))/4}}}
{{{x = (5/4)+7/4}}} 
{{{x = 12/4}}}
{{{x = 3}}} or
{{{x = (5/4)-7/4}}}
{{{x = -2/4}}}
{{{x = -1/2}}}

You can use the above as a guide to solve problem 2.