Question 1050488
x intercept of 11 is (11,0)
y-intercept of -2 is (0.-2)
The slope of that line is -2/-11 or 2/11
It passes through (0,-2), so the equation is y=(2/11)x-2 
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The slope of f is the negative reciprocal of 2/11 or -11/2
It has a point of (-4,8)
slope intercept form os y-y1=m(x-x1), where m is the slope, and (x1,y1) is a point
y-8=(-11/2)(x+4)
y-8=(-11/2)x-22
y=(-11/2)x+14
{{{graph(300,300,-15,15,-15,15,(2x/11)-2,(-11x/2)+14)}}}