Question 1050495
Let {{{ s }}} = the speed of the slower car in mi/hr
{{{ s + 15 }}} = the speed of the faster car in mi/hr
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Think of this as one car standing still and the other
car moving at the sum of their speeds
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{{{ 570 = ( s + s + 15 )*6 }}}
{{{ 570  = ( 2s + 15 )*6 }}}
{{{ 570 = 12s + 90 }}}
{{{ 12s = 480 }}}
{{{ s = 40 }}}
and
{{{ s+ 15 = 55 }}}
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The faster car's speed is 55 mi/hr
The slower car's speed is 40 mi/hr
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check answers:
{{{ d[1] = 40*6 }}}
{{{ d[1] = 240 }}} mi
and
{{{ d[2] = 55*6 }}}
{{{ d[2] = 330 }}} mi
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{{{ d[1] + d[2] = 240 + 330 }}}
{{{ d[1] + d[2] = 570 }}} mi
OK