Question 1050388
.
one can juice is 30% juice and another is 5% juice. How many liters of each should be mixed togther to get 25liters that is 28%juice
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<pre>
The equation of the pure juice content is this

0.3x + 0.05*(25-x) = 0.18*25,

where x is unknown volume in liters of the 30% juice.

Simplify and solve:

0.3x + 0.05*25 - 0.05x = 4.5,

0.25x + 1.25 = 4.5  --->  0.25x = 4.5 - 1.25  --->  0.25x = 3.25  --->  x = {{{3.25/0.25}}} = 13.

<U>Answer</U>. 13 liters of the 30% juice and (25-13) = 12 liters of the 5% juice.
</pre>

For detailed solutions of mixture problems see the lessons 

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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/mixtures/More-Mixture-problems.lesson>More Mixture problems</A>

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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/mixtures/Word-problems-on-mixtures-for-alloys.lesson>Word problems on mixtures for alloys</A> 

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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/mixtures/OVERVIEW-of-lesson-on-word-problems-for-mixtures.lesson>OVERVIEW of lessons on word problems for mixtures</A>

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