Question 1050425
The length of a rectangle  exceeds its width by 4 feet if the width is doubled and the length is decreased by 2 feet a new rectangle is formed whose perimeter is 8 feet more than the perimeter of the original rectangle find the dimensions for the original rectangle

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original rectangle

L-w=4
p=2L+2w
p={{{8+4w}}}


2w
L-2

p={{{2L-4+4w}}}

then it says 
2L+4w-4= 8+4w+8

L=10

original rec
L=10
W=6

check
your self!