Question 1050333

I need help with this system of equations the substitution method 
Here's the problem: 2x+10y=4 and x=8-5y and I substituted the x=8-5y in for x and I got 2(8-5y)+10y=4 then I did the distributing and got 16-10y+10y=4 which I discovered was 0 after i combined them. And now I'm not sure where to go from here. So if you can please help me.
<pre>Continue to get: - 10y + 10y = 4 - 16
Now, {{{0 <> - 12}}}, and therefore, this system has NO SOLUTIONS, which indicates that the lines are parallel.