Question 1050204
Use Cramer's rule,
{{{A=(matrix(3,3,
12,6,7,
7,-5,-6,
1,1,0))}}}
{{{abs(A)=120}}}
.
.
.
{{{A[x]=(matrix(3,3,
-35,6,7,
200,-5,-6,
-10,1,0))}}}
{{{abs(A[x])=1200}}}
.
.
.
{{{A[y]=(matrix(3,3,
12,-35,7,
7,200,-6,
1,-10,0))}}}
{{{abs(A[y])=-2400}}}
.
.
.
{{{A[z]=(matrix(3,3,
12,6,-35,
7,-5,200,
1,1,-10))}}}
{{{abs(A[z])=-600}}}
.
.
.
SO then,
{{{x=abs(A[x])/abs(A)=1200/120=10}}}
{{{y=abs(A[y])/abs(A)=-2400/120=-20}}}
{{{z=abs(A[z])/abs(A)=-600/120=-5}}}