Question 1050207
Let the first number be {{{x}}}, then the second number is {{{2x}}}, the third number is {{{(x+100)}}}
The sum of these three numbers is {{{x+2x+(x+100)}}}
{{{x+2x+x+100=336}}}
{{{4x=336-100}}}
{{{4x=236}}}
{{{x=236/4}}}
{{{x=59}}}
The first number is {{{59}}}, the second number is {{{2*59=118}}}, the third number is {{{59+100=159}}}
Answer: 59, 118, 159