Question 91701
A force of 50 pounds stretches a spring 1.5 inches. (Hooke's Law) 
(a.) Write the force F as a function of the distance x the spring is stretched. 
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Amount of force and stretch are directly related:
F = kx
50 = k*1.5
k = 10/0.3
k = 100/3 
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EQUATION:
F = (100/3)x
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Cheers,
Stan H.