Question 1050162
hi, i am having trouble solving these , would you be so kind to explain how to determine whether the equation defines Y as a function of X: 
1. 6x+3y^2=7 
2. square root (6x) +y=5 
3. 5x^2+y^3=27 
4. 4x+ IyI=3

solve for y

1. {{{6x+3y^2=7}}} 
1. {{{3y^2=7-6x}}}

1. {{{y^2=(7-6x)/(3)}}}

1. {{{y= +-sqrt((7-6x)/(3))}}}

2.{{{sqrt(6x) +y=5}}}
2.{{{y=5-sqrt(6x)}}}

3. {{{5x^2+y^3=27}}}
3. {{{y^3=27-5x^2}}}
3. {{{y=cbrt(27-5x^2)}}}

4. {{{4x+ IyI=3}}}
4. {{{IyI=(3-4x)}}}
meaning
{{{y=3-4x }}}

or
{{{-y=3-4x}}}
{{{y=4x-3}}}