Question 91660
{{{((x-2))/5}}} – {{{3/2}}} = {{{((x + 1))/10}}}
;
First, get rid of the denominators, multiply equation by 10 and you have:
{{{(2(x-2))/5}}} – {{{5(3/2)}}} = x + 1
;
Multiply what's inside of the brackets:
2x - 4 - 15 = x + 1
2x - 19 = x + 1
2x - x  = 1 + 19
x = 20
:
:
Check solution in original equation:
{{{((20-2))/5}}} – {{{3/2}}} = {{{((20 + 1))/10}}}
:
{{{18/5}}} – {{{3/2}}} = {{{21/10}}}
:
convert to common denominator of 10
{{{36/10}}} – {{{15/10}}} = {{{21/10}}}