Question 1049963
n=1
{{{f(1)}}}={{{3}}} first term is 3.

n=2


{{{f(n)}}}={{{-2f(n-1)+1}}}
{{{f(2)}}}={{{-2f(1)+1}}}
{{{f(2)}}}={{{-2*(3)+1}}}
{{{f(2)}}}={{{-5}}}

n=3

{{{f(3)}}}={{{-2f(2)+1}}}
{{{f(3)}}}={{{11}}}

n=4


{{{f(4)}}}={{{-2f(3)+1}}}
{{{f(4)}}}={{{-21}}}

n=5


{{{f(5)}}}={{{-2f(4)+1}}}
{{{f(5)}}}={{{43}}}