Question 1049970
 Solve this Triangle 
Angle B is 103 degrees and side a is 13.1cm and side c is 10.0cm 
Use the Law of Cosines to get:
b^2 = a^2 + c^2 - 2ac*Cos(B)
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b^2 = 330.54
b = 18.18
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Use the Law of Sines to get:
Sin(A)/Sin(B) = a/b
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Sin(A) = (13.1/18.18)*Sin(103) = 0.7021
A = arcsin(0.7021) = 44.6 degrees
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C = 180-(103+44.6) = 32.4 degrees
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Use Law of Sines to solve for "c"::
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Cheers,
Stan H.
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