Question 1049961
 Can a given angle &#945; satisfy both cos &#945; > 0 and sec &#945; < 0? Explain?
Ans: No, because sec is the multiplicative inverse of cos
sec(t) = 1/cos(t)
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If, for some particular angle &#952;, sec &#952;< 0 and csc &#952; < 0, in what quadrant must &#952; lie? What is the sign of cot&#952;>
If sec(t) < 0, t is in QII or QIII
If csc(t) < 0, t is in QIII or QIV
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Ans: t is in QIII
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Ans: cot(t) = cos(t)/sin(t) = (1/sin)(1/sec) = csc*(1/sec) = -*(1/-) = +
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Cheers,
Stan H.
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