Question 1049884
{{{(x + 2yi)^2}}} = {{{xi}}}

{{{(x^2 + 4xyi+4y^2i^2)}}} = {{{xi}}}

{{{(x^2 + 4xyi+4y^2(-1))}}} = {{{xi}}}

{{{x^2 -4y^2}}} = {{{xi-4xyi}}}
{{{x^2 -2^2*y^2}}} = {{{xi-4xyi}}}

{{{(x-2y)(x+2y)}}} = {{{xi-4xyi}}}
{{{(x-2y)(x+2y)}}} = {{{xi}}}{{{(1-4y)}}}
{{{(x-2y)(x+2y)/(1-4y)}}} = {{{xi}}}