Question 1049816

the {{{x}}} and {{{y}}} intercept of {{{4x-3y = 12}}}:

to find the {{{x}}}  intercept, set {{{y=0}}} and solve for {{{x}}}

{{{4x-3*0 = 12}}}

{{{4x= 12}}}

{{{x= 12/4}}}

{{{x= 3}}}


to find the {{{y}}}  intercept, set {{{x=0}}} and solve for {{{y}}}

{{{4*0-3y = 12}}}

{{{-3y = 12}}}

{{{y = 12/-3}}}

{{{y = -4}}}

so,

the {{{x}}}  intercept is at ({{{3}}},{{{0}}})

the {{{y}}}  intercept is at ({{{0}}},{{{-4}}})


{{{ graph( 600, 600, -10, 10, -10, 10, (4/3)x-4) }}}