Question 1049756

 given:
 {{{f(0) = 2 }}} and 
{{{f(n+1) = -2f(n) + 3 }}}for {{{n >= 0}}}, 

here is the sequence for the first three numbers:
 
{{{n = 0}}}:
 
{{{f(0+1) = -2 * f(0) + 3}}}
{{{f(1) = -2 * 2 + 3}}}
{{{f(1) = -4 + 3}}}
{{{f(1) = -1}}}
 
{{{n = 1}}}:
 
{{{f(1+1) = -2 * f(1) + 3}}}
{{{f(2) = -2 *( -1) + 3}}}
{{{f(2) = 2 + 3}}}
{{{f(2) = 5}}}

{{{n = 2}}}
 
{{{f(3) = -2 * f(2) + 3}}}
{{{f(3) = -2 * 5 + 3}}}
{{{f(3) = -10 + 3}}}
{{{f(3) = -7}}}


so,  {{{f(2)}}} is equal to {{{5}}} and your answer is C.