Question 1049384
{{{-16t^2+32t+6=0}}}
{{{t = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{t = (-32 +- sqrt( 32^2-4*(-16)*6 ))/(2*a) }}}
{{{t = (-32 +- sqrt( 1408 ))/(2*(-16)) }}}
{{{t = (-32 - sqrt( 1408 ))/(-32) =-0.17260394}}} or {{{t = (-32 + sqrt( 1408 ))/(-32) =2.17260394}}}
{{{t=-0.17260394}}} or {{{t=2.17260394}}}