Question 1049417
Put in the simplest form each of :
(1) 5/1-2i

(2) 2+3i/2-3i
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Multiply the NUM and the DEN by the conjugate of the DEN
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(2+3i)*(2+3i)/((2-3i)/(2+3i)) = (2+3i)^2/(4+9)
= {{{4 + 12i - 9)/13}}}
= {{{(-5 + 12i)/13}}}
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Do the 1st one the same way.
It's simpler.