Question 1049503

{{{h(x) = 5/ (sqrt (2x+10 ))}}} in a domain will be all values of {{{x}}} except the value that makes {{{sqrt (2x+10 )}}} equal to zero and that is

{{{sqrt (2x+10 )=0}}}

{{{2x+10 =0}}}

{{{2x=-10}}}

{{{x=-10/2}}}

{{{x=-5}}}


so, we will exclude {{{-5}}} and domain is: { {{{x}}} element {{{R}}} : {{{x<>-5}}} }