Question 1049515
Line y = {{{highlight_green(-2)x + b}}}
tangent to:
f(x)= -2x^2 - 16x- 33
f' = -4x - 16 = slope of tangent line
-2 = -4x - 16
x = -7/2
f(-7/2) = -3/2
P(-7/2, -3/2) Point of Intersection
***Using point-slope form, {{{y - y[1] = highlight_green(m)(x - x[1])}}}
y + 3/2= -2(x+7/2)
y = -2x -17/2

{{{drawing(300,300,     -10,10,-10,10,  
 grid(1),
circle(0,-8.5,0.4),
circle(-3.5,-1.5,0.4),
graph( 300, 300,  -10,10,-10,10,   0, -2x^2 - 16x- 33, -2x- 17/2))}}}