Question 1049487

Please help me with this question.


Use properties of logarithms to solve the equation. Make sure to check the validity
of your solution:
log2 x + log2 3 = 2
<pre>{{{log (2, x) + log (2, 3) = 2}}}
{{{log (2, 3x) = 2}}} ----- Applying {{{log (a, b) + log (a, c) = log (a, bc)}}}
{{{3x = 2^2}}} -------- Converting to EXPONENTIAL form
3x = 4
{{{highlight_green(matrix(1,3, x = 4/3, or, 1&1/3))}}}