Question 1049442
answer both
a.
{{{10}}}=4*{{{(y-1)}}}
{{{10/4}}}={{{(y-1)}}}
{{{5/2}}}={{{(y-1)}}}
{{{5/2+1}}}={{{(y)}}}
{{{5/2+2/2}}}={{{(y)}}}
{{{(5+2)/2}}}={{{(y)}}}
{{{7/2}}}={{{(y)}}}
b.
{{{10}}}=4*{{{(y-1)}}}
{{{10}}}={{{(4y-4)}}}
{{{14}}}={{{(4y)}}}
{{{14/4}}}={{{(y)}}}
{{{7/2}}}={{{(y)}}}

both give same result but distributive property is faster in this case