Question 1049367
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The length of a rectangle is 5 less than twice its width. The perimeter is 26 meters. Find the dimensions of the rectangle.
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<pre>
Let W = width.
Then the length is 2W-5.

The perimeter equation is

W + (2W-5) + W + (2W-5) = 26,  or

6W - 10 = 26,  or

6W = 36.

From this point please complete the solution on your own.
</pre>

I noticed that this problem is the third today of the same type of problems.


In the lesson 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/Points-lines-and-rays/Solved-problems-on-the-perimeter-and-side-lengths-of-a-rectangle.lesson>Solved problems on the perimeter and side lengths of a rectangle</A> 

there are many solved problems of this type.


They are good samples for you.
Read the lesson and become a trained person in solving such problems.


It would be much better for you to learn on how to solve such simple problems instead of posting them one after another.


You are always welcome in this site!