Question 1049311
Use Cramer's rule,
{{{A=(matrix(3,3,
1,-1,3,
1,-2,0,
2,-2,5))}}}
{{{abs(A)=1}}}
.
.
.
{{{A[x]=(matrix(3,3,
6,-1,3,
5,-2,0,
9,-2,5))}}}
{{{abs(A[x])=-11}}}
.
.
.
{{{A[y]=(matrix(3,3,
1,6,3,
1,5,0,
2,9,5))}}}
{{{abs(A[y])=-8}}}
.
.
.
{{{A[z]=(matrix(3,3,
1,-1,6,
1,-2,5,
2,-2,9))}}}
{{{abs(A[z])=3}}}
.
.
.
So then,
{{{x=abs(A[x])/abs(A)=-11/1=-11}}}
{{{y=abs(A[y])/abs(A)=-8/1=-8}}}
{{{z=abs(A[z])/abs(A)=3/1=3}}}