Question 1049378
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The length of a rectangle is 6 ft more than its width. The perimeter of the rectangle is 68 ft. What are the dimensions of the rectangle?

Let w represent the width of the rectangle.
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<pre>
Let W represents the width of the rectangle.
Then its length is W+6.

Then the perimeter is 2W + 2(W+6).

Then for the perimeter you have an equation

2W + 2W + 12 = 68.

4W = 68 - 12,

4W = 56,

W = {{{56/4}}} = 14.

<U>Answer</U>.  The width is 14 ft, the length is 20 ft.
</pre>

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