<PRE><B>Question 1049391</B>
First find the slope of your original line.
{{{2x+3y=7}}}
{{{3y=-2x+7}}}
{{{y=-(2/3)x+7/3}}}
{{{m[1]=-2/3}}}
Perpendicular lines have slopes that are negative reciprocals,
{{{m[1]m[2]=-1}}}
{{{-(2/3)m[2]=-1}}}
{{{m[2]=3/2}}}
So then use the point slope form with this slope and the point,
{{{y-5=(3/2)(x-(-3))}}}
{{{2y-10=3(x+3)}}}
{{{2y-10=3x+9}}}
{{{-3x+2y=19}}}
{{{3x-2y=-19}}}
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*[illustration dfrf1.JPG].</PRE>