Question 1049260
11p+3q=66 ===> {{{q = 22-(11/3)p}}}


===> {{{2p^2 =10-p+q = 10-p+  22-(11/3)p = 32 - (14/3)p}}}


===> {{{2p^2 = 32 - (14/3)p}}}  ===>  {{{3p^2 + 7p -48 = 0}}}


===> (p-3)(3p +16) = 0  ====> p = 3, -16/3.


===> equilibrium price is 3 currency units, and equilibrium quantity is q = 11 units.