Question 1049300

{{{(3/2)x - (5/4)y = 15 }}}

 in {{{y=mx+b}}}

{{{m}}} is your rate of change

 you need to get {{{y}}} by itself 

{{{(3/2)x - 15 = (5/4)y }}}

{{{3x/2 - 30/2 = (5/4)y }}}

{{{(3x - 30)/2 = (5/4)y }}}

{{{3x - 30 = 2(5/4)y }}}

{{{3x - 30 = cross(2)(5/cross(4)2)y }}}

{{{3x - 30 = (5/2)y }}}

{{{2*3x - 2*30 = 2(5/2)y }}}

{{{6x - 60 = 5y }}}

{{{6x/5 - 60/5 = 5y/5 }}}

{{{y=highlight((6/5))x - 12 }}}

so,the rate of change is {{{highlight(6/5) }}}