Question 1049232
if a length of {{{6}}} and a width {{{5x+8}}}, and the area is {{{80}}}, we have

{{{6(5x+8)=80}}}

{{{30x+48=80}}}

{{{30x=80-48}}}

{{{30x=32}}}

{{{x=32/30}}}

{{{x=16/15}}}

then a width is

{{{5x+8=5(16/15)+8}}}

{{{5x+8=(16/3)+8}}}

{{{5x+8=16/3+24/3}}}

{{{5x+8=40/3}}}

check the area:

{{{length*width=80}}}

{{{6*(40/3)=80}}}

{{{cross(6)2*(40/cross(3)1)=80}}}

{{{2*40=80}}}

{{{80=80}}}