Question 1049030
Coefficient on the leading term is POSITIVE 2.  This parabola is concave upward, or convex downward; the  vertex is a minimum.


{{{2x^2-2x=0}}}
{{{2x(x-1)=0}}}
{{{x(x-1)=0}}}
The x-intercepts are at  0 and 1.  Because of symmetry the vertex (minimum point) will be at the exact middle of 0 and 1; or at {{{x=1/2}}}.


{{{f(1/2)=2(1/2)^2-2(1/2)}}}-----compute this.