Question 1049054
Lashonda has two solutions that contain alcohol and is mixing them with each other.
 She uses 4 times as much Solution A as Solution B.
 Solution A is 13% alcohol and Solution B is 18% alcohol.
 How many milliliters of Solution B does she use, if the resulting mixture has 350 milliliters of pure alcohol?
:
let b = amt of solution B required
"She uses 4 times as much Solution A as Solution B." therefore:
a = 4b 
:
Amt of alcohol in A + amt of alcohol in B = 350 ml of alcohol
.13(4b) + .18b = 350 
.52b + .18b = 350
.7b = 350
b = 350/.7
b = 500 ml of B solution required