Question 91500
3X+4Y=12 NOW SUBSTITUTE 0 FOR X & SOLVE FOR Y:
3*0+4Y=12
4Y=12
Y=12/4
Y=3 ANSWER IS (0,3)
3*2/3+4Y=12
6/3+4Y=12
2+4Y=12
4Y=12-2
4Y=10
Y=10/4
Y=5/2 ANSWER (2/3,5/2)
3X+4*0=12
3X=12
X=12/3
X=4 ANSWER (4,0)
3*-2/3+4Y=12
-6/3+4Y=12
-2+4Y=12
4Y=12+2
4Y=14
Y=14/4
Y=7/2 ANSWER (-2/3,7/2)
{{{ graph( 300, 200, -6, 5, -10, 10, y = -3x/4 +3) }}} (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -3x/4 +3).