Question 1048919
 For the parabola whose equation is​ given, determine whether it opens upward or​ downward, find the​ vertex, and find the​ x- and​ y-intercepts. Then graph the parabola.
​f(x)=x squared minus 2 x minus 48 
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f(x) = x^2 - 2x - 48
a = 1 ; b = -2 ; c = -48
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opens upward because a is positive
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Vertex::
x = -b/(2a) = 2/2 = 1 ; f(1) = 1^2-2*1-48 = -49
Vertex is (1,-49)
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x-intercept:: 
Let y = 0 ; solve for "x"::
x^2-2x-48 = 0
(x-8)(x+6) = 0
x-intercepts:: x = 8 ; x = -6
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y-intercept::
Let x = 0 ; solve for "y"::
y = 0^2 - 2*0 - 48
y = -48
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Graph::
{{{graph(400,400,-20,20,-60,60,x^2 - 2x - 48)}}}
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Cheers,
Stan H.
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