Question 91492
Let x=the tens digit
And let y=the units digit

Then the number (N)=10x+y

Now we are told that:

10x+y=6(x+y)-----------------------eq1

We are also told that:

x=y+1-------------------eq2

Lets simplify eq1:

10x+y=6(x+y)  get rid of parens
10x+y=6x+6y  subtract y and also 6x from both sides

10x+y-y-6x=6x-6x+6y-y  collect like terms

4x=5y  divide both sides by 4

x=(5/4)y-------------------------eq1

substitute x=(5/4)y into eq2 and we get

(5/4)y=y+1  multiply both sides by 4

5y=4y+4  subtract 4y from both sides

5y-4y=4

y=4------------------the unit digit

substitute y=4 into eq1:

x=(5/4)*4=20/4=5-----------------------the tens digit

The number =10x+y=10*5+4=54---------the number

CK

sum of digits is 5+4=9
54=6*9

the tens digit,5, is 1 greater than the unit digit 4


Hope this helps---ptaylor