Question 1048798
Let the original fraction be 

{{{A = x/y}}}
Then {{{y = x+4}}} so {{{A = x/(x+4)}}}

Also:
{{{(x+4)/(x+4+7) = 1/2}}} 
{{{(x+4)/(x+11) = 1/2}}} 
{{{2*(x+4) = x+11}}} 
{{{2*x+8 = x+11}}}
{{{x = 3}}}
So the original fraction is 3/7 and the second is 7/14.