Question 1048766
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Distance equals rate times time, so the distance on the faster part of the trip is equal to *[tex \Large 4(r\ +\ 5)], and the distance on the slower part of the trip is equal to *[tex \Large 5r].  Presumably, neither California nor the place Billy started moved during the trip so we can assume that these two distances are the same.  Therefore:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  5r\ =\ 4(r\ +\ 5)]


Solve for *[tex \Large r] and then calculate *[tex \Large r\ +\ 5]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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