Question 1048590
sean had some money: {{{x}}} dollars

he used {{{(2/3)x}}}  to buy a watch 
remainder will be  {{{x-(2/3)x=(3/3)x-(2/3)x=(1/3)x}}}

and spent {{{3/4}}} of the remainder on a wallet, that is {{{(3/4)(1/3)x=(3/12)x}}}

if the watch cost {{{65}}} dollars {{{more}}} than the wallet, we have

{{{(2/3)x=(3/12)x+65}}} ......solve for {{{x}}}
{{{4(2/(3*4))x=(3/12)x+65}}}

{{{(8/12)x-(3/12)x=65}}}

{{{(5/12)x=65}}}

{{{5x=65*12}}}

{{{5x=780}}}

{{{x=780/5}}}

{{{x=156}}}


so,  a watch cost {{{x=(2/3)x}}}->{{{x=(2/3)156}}}->{{{x=104}}}dollars
remainder will be  {{{(1/3)x=(1/3)156}}}->{{{(1/3)x=52}}}

{{{3/4}}} of the remainder on a wallet, that is {{{(3/4)52=39}}}

so,a watch cost {{{x=104}}} and a watch cost {{{39}}}dollars

how much did sean had left: {{{x-(watch+watch)cost=156-(104+39)=156-143=13}}}

how much money did sean have at first :{{{156}}} dollars